python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1how to find index of list of list in python
[(i, colour.index(c))
for i, colour in enumerate(colours)
if c in colour]choose index from list python
ahahfunny = ['ahah ', 'copy-', 'paste ', 'stack overflow', ' go ', 'brr']
# The biggest index is 5. Reason why it isn't 6 is because according to the
# computer index 0 = 1, 1 = 2, 2 = 3, etc...
print(ahahfunny[0]) # It should print 'ahah', being the first index of the list
n = 0
for i in range(len(ahahfunny)):
print(ahahfunny[n] + 'n')
n += 1
print(ahahfunny[0], ahahfunny[3], ahahfunny[4], ahahfunny[5])
print("nbrrrtYou're welcometbrrr.")Copyright © 2021 Codeinu
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