python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python find in list
# There is several possible ways if "finding" things in lists.
'Checking if something is inside'
3 in [1, 2, 3] # => True
'Filtering a collection'
matches = [x for x in lst if fulfills_some_condition(x)]
matches = filter(fulfills_some_condition, lst)
matches = (x for x in lst if x > 6)
'Finding the first occurrence'
next(x for x in lst if ...)
next((x for x in lst if ...), [default value])
'Finding the location of an item'
[1,2,3].index(2) # => 1
[1,2,3,2].index(2) # => 1
[1,2,3].index(4) # => ValueError
[i for i,x in enumerate([1,2,3,2]) if x==2] # => [1, 3]find an index of an item in a list python
#Example List
list = ['apples', 'bannas', 'grapes']
#Use Known Entites In The List To Find The Index Of An Unknown Object
Index_Number_For_Bannas = list.index('apples')
#Print The Object
print(list[Index_Number_For_Bannas])python index method
my_string = "Hello World!"
my_string.index("l") # outputs 2
# this method only outputs the index of the first "l" value in the string/listfind in python
def find_all_indexes(input_str, search_str):
l1 = []
length = len(input_str)
index = 0
while index < length:
i = input_str.find(search_str, index)
if i == -1:
return l1
l1.append(i)
index = i + 1
return l1
s = 'abaacdaa12aa2'
print(find_all_indexes(s, 'a'))
print(find_all_indexes(s, 'aa'))python find if part of list is in list
'''
check if list1 contains all elements in list2
'''
result = all(elem in list1 for elem in list2)
if result:
print("Yes, list1 contains all elements in list2")
else :
print("No, list1 does not contains all elements in list2"Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
