get all indices of a value in list python
indices = [i for i, x in enumerate(my_list) if x == "whatever"]get all indices of a value in list python
indices = [i for i, x in enumerate(my_list) if x == "whatever"]python find index by value
>>> ["foo", "bar", "baz"].index("bar")
1python find in list
# There is several possible ways if "finding" things in lists.
'Checking if something is inside'
3 in [1, 2, 3] # => True
'Filtering a collection'
matches = [x for x in lst if fulfills_some_condition(x)]
matches = filter(fulfills_some_condition, lst)
matches = (x for x in lst if x > 6)
'Finding the first occurrence'
next(x for x in lst if ...)
next((x for x in lst if ...), [default value])
'Finding the location of an item'
[1,2,3].index(2) # => 1
[1,2,3,2].index(2) # => 1
[1,2,3].index(4) # => ValueError
[i for i,x in enumerate([1,2,3,2]) if x==2] # => [1, 3]find item in list
def findNumber(arr, k):
if k in arr:
print("YES")
else:
print("NO")python find if part of list is in list
'''
check if list1 contains all elements in list2
'''
result = all(elem in list1 for elem in list2)
if result:
print("Yes, list1 contains all elements in list2")
else :
print("No, list1 does not contains all elements in list2"Copyright © 2021 Codeinu
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