Answers for "sum of digits of 2^n when n is large"

1

Determine the sum of al digits of n

def sum_of_digits(n): 
	sum = 0
	while (n != 0): 
		sum = sum + int(n % 10) 
		n = int(n/10) 
	return sum
Posted by: Guest on October-20-2020

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