convert 2d list to 1d python
import itertools
a = [[1, 2], [3, 4], [5, 6]]
list(itertools.chain.from_iterable(a))
Output:- [1, 2, 3, 4, 5, 6]convert 2d list to 1d python
import itertools
a = [[1, 2], [3, 4], [5, 6]]
list(itertools.chain.from_iterable(a))
Output:- [1, 2, 3, 4, 5, 6]numpy convert 1d array to 2d
import numpy as np
# 1D array
one_dim_arr = np.array([1, 2, 3, 4, 5, 6])
# to convert to 2D array
# we can use the np.ndarray.reshape(shape) function
# here shape is given by two integers seperated by a comma
# the two integers specify m,n for the new matrix
# ensure that the matrix that you are trying to generate
# has a size that meets the number of elements in the 1D array.
# for that make sure that
# m * n = number of elements in the one dimentional array
two_dim_arr = one_dim_arr.reshape(1, 6)
#which returns a 2D array
print(two_dim_arr)
# confirmed by the array.ndim attribute
print(two_dim_arr.ndim)
# you can even specify one of the dimensions as unknown by passing -1
# numpy will infer the length using the array and remaining dimensions
two_dim_arr = one_dim_arr.reshape(1,-1)array 2d to 1d
int array[width * height];
int SetElement(int row, int col, int value)
{
array[width * row + col] = value;
}pass 2d array to 1d python
# Create a 2D Numpy Array.
arr = np. array([[0, 1, 2],
[3, 4, 5],
[6, 7, 8]])
# convert 2D array to a 1D array of size 9.
flat_arr = np. reshape(arr, 9)Copyright © 2021 Codeinu
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