Answers for "* pattern in python"

6

pattern in python

rows = 6                        #Pattern(1,121,12321,1234321,123454321)
for i in range(1, rows + 1):
    for j in range(1, i - 1):
        print(j, end=" ")
    for j in range(i - 1, 0, -1):
        print(j, end=" ")
    print()
Posted by: Guest on December-21-2020
0

* pattern by python

def pattern(n):    
  for i in range(0,n):       
    for j in range(0, i+1): 
      print("* " , end="")         
      print("r") pattern(5
Posted by: Guest on December-02-2020
0

* pattern program in python

def pattern(n):     for i in range(0,n):         for j in range(0, i+1):              print("* " , end="")         print("r") pattern(5)
Posted by: Guest on August-21-2020
-1

python pattern

python
        
            
        
     import re
v = "aeiou"
c = "qwrtypsdfghjklzxcvbnm"
print(*re.findall("(?=[%s]([%s]{2,})[%s])"%(c,v,c),input(), re.I) or [-1], sep="n")
Posted by: Guest on June-30-2021

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