python pop element
my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop()
-->[123, 'Add', 'Grepper'] #last element is removed
my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop(0)
-->['Add', 'Grepper', 'Answer'] #first element is removed
my_list = [123, 'Add', 'Grepper', 'Answer']
any_index_of_the_list = 2
my_list.pop(any_index_of_the_list)
-->[123, 'Add', 'Answer'] #element at index 2 is removed
#(first element is 0)python list safely pop
In [1]: from typing import List, Any
In [2]: x = [{"count": 100}, {"count": 30}]
# use this function
In [3]: def defaultable_pop(input_list: List, index: int, default_value: Any = None) -> Any:
...: try:
...: return input_list.pop(index)
...: except IndexError:
...: return default_value
...:
# list, index, (default of empty dict)
In [4]: y: int = defaultable_pop(x, 0, dict({})).get("count", 0)
In [5]: y
Out[5]: 100
# As opposed to:
# y: int = x[0].get("count", 0) if len(x) > 0 else 0python list pop
# removes last element of list unless parameter is given
l1 = [1,2,3,4,5]
print(l1.pop()) # returns [1, 2, 3, 4]
print(l1.pop(2)) # returns [1, 2, 4, 5] removes element at given indexCopyright © 2021 Codeinu
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