Answers for "python dict pop"

14

python pop element

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop()
-->[123, 'Add', 'Grepper'] #last element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop(0)
-->['Add', 'Grepper', 'Answer'] #first element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
any_index_of_the_list = 2
my_list.pop(any_index_of_the_list)
-->[123, 'Add', 'Answer'] #element at index 2 is removed 
						  #(first element is 0)
Posted by: Guest on March-23-2020
1

python dictionary pop key

my_dict.pop('key', None)
Posted by: Guest on October-17-2020
0

dict pop

dictionary.pop(key, default)
Posted by: Guest on July-31-2020

Python Answers by Framework

Browse Popular Code Answers by Language