Answers for "number of trailing zeros in a factorial of a number."

number of trailing zeros in factorial python

def findTrailingZeros(n):
 
    # Initialize result
    count = 0
 
    # Keep dividing n by
    # 5 & update Count
    while(n >= 5):
        n //= 5
        count += n
 
    return count
 
 
# Driver program
n = 100
print("Count of trailing 0s " +
      "in 100! is", findTrailingZeros(n))

trailing zeroes in factorial

#include <iostream>

using namespace std;

int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    int t;
    cin>>t;
    while(t--)
    {
        int n;
        cin>>n;
        int res=0;
        for(int i=5;i<=n;i=i*5)
        {
            res=res+n/i;
        }
        cout<<res<<endl;
    }
    return 0;
}

number of trailing zeros in a factorial of a number.

# Number of trailing zeros in a factorial of a number

def zeros(n)
  zeros = 0
  while (n > 0) 
    n = (n / 5).floor
    zeros += n
  end
  zeros  
end

print "Number of trailing zeros = ", zeros(6);   # 1
print "\nNumber of trailing zeros = ", zeros(30);  # 7

number of trailing zeros in a factorial of a number.

// Number of trailing zeros in a factorial of a number

fn zeros(mut n: u64) -> u64 {
    let mut zeros = 0;
    while n > 0 {
        n /= 5;
        zeros += n;
    }
    zeros
}

fn main() {
    println!("Number of trailing zeros = {} ", zeros(14));  // 2
    println!("Number of trailing zeros = {} ", zeros(30));  // 7
}