second max salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
second max salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
second highest salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
OR
Here is the solution for nth highest
salary from employees table
SELECT FIRST_NAME , SALARY FROM
(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
(ORDER BY SALARY DESC) AS SALARY_RANK
FROM EMPLOYEES)
WHERE SALARY_RANK = n;
first max salary in sql
SELECT first-name
FROM employees
WHERE salary = (SELECT MAX(salary) FROM employees);
sql highest salary by location
/* Highest salary by Department/Location */
SELECT e.ename, e.sal, e.deptno, d.loc
FROM emp e
JOIN dept d
ON e.deptno = d.deptno
WHERE e.sal in
(
select max(sal)
from emp
group by deptno
)
how to get employee having maximum experience in mysql
select max(salary), dept_id from employee where salary not in(select max(salary) from employee) group by dept_id;
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