finding duplicate column values in table with sql
SELECT username, email, COUNT(*) FROM users GROUP BY username, email HAVING COUNT(*) > 1
finding duplicate column values in table with sql
SELECT username, email, COUNT(*) FROM users GROUP BY username, email HAVING COUNT(*) > 1
sql how to duplicate a table
CREATE TABLE new_table LIKE original_table; INSERT INTO new_table SELECT * FROM original_table;
duplicate names in sql
• SELECT first_name, COUNT (first_name) FROM employees GROUP BY first_name HAVING (COUNT(first_name) > 1);
duplicate table sql
/* First step 1: Duplicate table in SQL (no data is coppied with) */ CREATE TABLE new_table LIKE original_table; /* Sec step 2 : Insert the data (copies the data from original to new) */ INSERT INTO new_table SELECT * FROM original_table; /*Done!*/
duplicate table sql
CREATE TABLE new_table LIKE original_table;
FIND DUPLICATES IN COLUMN SQL
declare @YourTable table (id int, name varchar(10), email varchar(50)) INSERT @YourTable VALUES (1,'John','John-email') INSERT @YourTable VALUES (2,'John','John-email') INSERT @YourTable VALUES (3,'fred','John-email') INSERT @YourTable VALUES (4,'fred','fred-email') INSERT @YourTable VALUES (5,'sam','sam-email') INSERT @YourTable VALUES (6,'sam','sam-email') SELECT name,email, COUNT(*) AS CountOf FROM @YourTable GROUP BY name,email HAVING COUNT(*)>1
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