postgres count distinct
SELECT
COUNT(DISTINCT column)
FROM
table_name
WHERE
condition;postgres count distinct
SELECT
COUNT(DISTINCT column)
FROM
table_name
WHERE
condition;postgresql left join distinct on
Select Distinct On (u.username, u.email)
u.username
,u.email
,l.browser
,l.login_time
From users u
Join logins l On l.username = u.username
Order By u.username, u.email, login_time Desc
^array aggre distinct postgres
SELECT ARRAY(SELECT DISTINCT e FROM unnest(ARRAY[a,b,c,d]) AS a(e))
FROM ( VALUES
('foo', 'bar', 'foo', 'baz' )
) AS t(a,b,c,d);Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us
