sql select between two dates
select Date, TotalAllowance from Calculation where EmployeeId = 1
and Date between '2011/02/25' and '2011/02/27'
sql select between two dates
select Date, TotalAllowance from Calculation where EmployeeId = 1
and Date between '2011/02/25' and '2011/02/27'
date difference in number of days sql server
DECLARE
@start_dt DATETIME2= '2019-12-31 23:59:59.9999999',
@end_dt DATETIME2= '2020-01-01 00:00:00.0000000';
SELECT
DATEDIFF(year, @start_dt, @end_dt) diff_in_year,
DATEDIFF(quarter, @start_dt, @end_dt) diff_in_quarter,
DATEDIFF(month, @start_dt, @end_dt) diff_in_month,
DATEDIFF(dayofyear, @start_dt, @end_dt) diff_in_dayofyear,
DATEDIFF(day, @start_dt, @end_dt) diff_in_day,
DATEDIFF(week, @start_dt, @end_dt) diff_in_week,
DATEDIFF(hour, @start_dt, @end_dt) diff_in_hour,
DATEDIFF(minute, @start_dt, @end_dt) diff_in_minute,
DATEDIFF(second, @start_dt, @end_dt) diff_in_second,
DATEDIFF(millisecond, @start_dt, @end_dt) diff_in_millisecond;
find difference in dates sql
SELECT DATEDIFF(day, date1,date2) AS DateDiff
/*
DATEDIFF accepts three arguments
1- day, month, year etc what form you need difference
2,3- dates
*/
sql get number of days between two dates
DATEDIFF(DAY, '1/1/2011', '3/1/2011')
how to get the date diff of 2 dates in the same fieldin sql server
WITH Partitioned AS( SELECT *, ROW_NUMBER() OVER (PARTITION BY cu_id, date ORDER BY cu_id, date) AS RowNumber FROM @Table) SELECT *, CASE WHEN RowNumber > 1 THEN 0 ELSE COALESCE(DATEDIFF(DAY, (SELECT MAX(date) FROM @Table WHERE date < a.date AND cu_id = a.cu_id), a.date), 0) END AS Days_betweenFROM Partitioned a
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