postgres date difference seconds
-- difference in seconds between two dates
select extract(epoch from ('2020-03-30 09:55:56'::timestamp - '2020-03-30 08:54:55'::timestamp));
-- result : 3661postgres date difference seconds
-- difference in seconds between two dates
select extract(epoch from ('2020-03-30 09:55:56'::timestamp - '2020-03-30 08:54:55'::timestamp));
-- result : 3661postgresql get difference in hours between two dates
select EXTRACT(
EPOCH FROM now() - (now() - INTERVAL '5 HOUR')
)/3600
-- it will return 5DATEDIFF minute postgres
-- Difference between Dec 30, 2011 08:54:55 and Dec 30, 2011 08:56:10 in minutes
SELECT (DATE_PART('day', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp) * 24 * 60 +
DATE_PART('hour', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp)) * 60 +
DATE_PART('minute', '2011-12-30 08:56:10'::timestamp - '2011-12-30 08:54:55'::timestamp);
-- Result: 1
-- Time only
SELECT DATE_PART('hour', '08:56:10'::time - '08:54:55'::time) * 60 +
DATE_PART('minute', '08:56:10'::time - '08:54:55'::time);
-- Result: 1postgres time difference in minutes
CREATE OR REPLACE FUNCTION DateDiff (units VARCHAR(30), start_t TIME, end_t TIME)
RETURNS INT AS $$
DECLARE
diff_interval INTERVAL;
diff INT = 0;
BEGIN
-- Minus operator for TIME returns interval 'HH:MI:SS'
diff_interval = end_t - start_t;
diff = DATE_PART('hour', diff_interval);
IF units IN ('hh', 'hour') THEN
RETURN diff;
END IF;
diff = diff * 60 + DATE_PART('minute', diff_interval);
IF units IN ('mi', 'n', 'minute') THEN
RETURN diff;
END IF;
diff = diff * 60 + DATE_PART('second', diff_interval);
RETURN diff;
END;
$$ LANGUAGE plpgsql;Copyright © 2021 Codeinu
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