INU Login Sign up
Login Or Sign up

Answers for "sqlite3 connect code python"

SQL
2

sqlite python connection

import sqlite3

try:
    sqliteConnection = sqlite3.connect('SQLite_Python.db')
    cursor = sqliteConnection.cursor()
    print("Database created and Successfully Connected to SQLite")

    sqlite_select_Query = "select sqlite_version();"
    cursor.execute(sqlite_select_Query)
    record = cursor.fetchall()
    print("SQLite Database Version is: ", record)
    cursor.close()

except sqlite3.Error as error:
    print("Error while connecting to sqlite", error)
finally:
    if (sqliteConnection):
        sqliteConnection.close()
        print("The SQLite connection is closed")
Posted by: Guest on July-27-2020
2

sqlite3 python

import sqlite3 as lite 
import sys 
 
try: 
    con = lite.connect('products.db') 
    cur = con.cursor()     
    cur.execute("CREATE TABLE drinks(Id INTEGER PRIMARY KEY AUTOINCREMENT, Name TEXT, Price REAL)") 
    cur.execute("CREATE TABLE fruits(Id INTEGER PRIMARY KEY AUTOINCREMENT, Name TEXT, Price REAL)") 
    con.commit() 
             
except e: 
    if con: 
        con.rollback() 
     
    print("Unexpected error %s:" % e.args[0]) 
    sys.exit(1) 
finally: 
    if con: 
        con.close()
Posted by: Guest on February-07-2021

Code answers related to "sqlite3 connect code python"

Code answers related to "SQL"

Browse Popular Code Answers by Language

Python
Javascript
Whatever
Shell/Bash
CSS
Html
PHP
SQL
Java
C#

Popular Programming Languages

Abap ActionScript Assembly BASIC C C# C++ Clojure Cobol CSS Dart Delphi Elixir Erlang F# Fortran Go Groovy Haskell Html Java Javascript Julia Kotlin Lisp Lua Matlab Objective-C Pascal Perl PHP Prolog Python R Ruby Rust Scala Scheme Shell/Bash SQL Swift TypeScript VBA Whatever

Advertisements

290x500

Company

Compilers

Help

Connect with us

footer logo

Copyright © 2021 Codeinu