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Answers for "python sqllite"

SQL
2

sqlite python connection

import sqlite3

try:
    sqliteConnection = sqlite3.connect('SQLite_Python.db')
    cursor = sqliteConnection.cursor()
    print("Database created and Successfully Connected to SQLite")

    sqlite_select_Query = "select sqlite_version();"
    cursor.execute(sqlite_select_Query)
    record = cursor.fetchall()
    print("SQLite Database Version is: ", record)
    cursor.close()

except sqlite3.Error as error:
    print("Error while connecting to sqlite", error)
finally:
    if (sqliteConnection):
        sqliteConnection.close()
        print("The SQLite connection is closed")
Posted by: Guest on July-27-2020
2

sqlite3 python

import sqlite3 as lite 
import sys 
 
try: 
    con = lite.connect('products.db') 
    cur = con.cursor()     
    cur.execute("CREATE TABLE drinks(Id INTEGER PRIMARY KEY AUTOINCREMENT, Name TEXT, Price REAL)") 
    cur.execute("CREATE TABLE fruits(Id INTEGER PRIMARY KEY AUTOINCREMENT, Name TEXT, Price REAL)") 
    con.commit() 
             
except e: 
    if con: 
        con.rollback() 
     
    print("Unexpected error %s:" % e.args[0]) 
    sys.exit(1) 
finally: 
    if con: 
        con.close()
Posted by: Guest on February-07-2021
2

python sqlite

import sqlite3

con = sqlite3.connect(":memory:")
con.isolation_level = None
cur = con.cursor()

buffer = ""

print("Enter your SQL commands to execute in sqlite3.")
print("Enter a blank line to exit.")

while True:
    line = input()
    if line == "":
        break
    buffer += line
    if sqlite3.complete_statement(buffer):
        try:
            buffer = buffer.strip()
            cur.execute(buffer)

            if buffer.lstrip().upper().startswith("SELECT"):
                print(cur.fetchall())
        except sqlite3.Error as e:
            print("An error occurred:", e.args[0])
        buffer = ""

con.close()
Posted by: Guest on August-02-2021

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