how to create foreign key in sql oracle

how to create table in oracle sql syntax example and foreign key

CREATE TABLE hr.admin_emp (
         empno      NUMBER(5) PRIMARY KEY,
         ename      VARCHAR2(15) NOT NULL,
         ssn        NUMBER(9) ENCRYPT,
         job        VARCHAR2(10),
         mgr        NUMBER(5),
         hiredate   DATE DEFAULT (sysdate),
         photo      BLOB,
         sal        NUMBER(7,2),
         hrly_rate  NUMBER(7,2) GENERATED ALWAYS AS (sal/2080),
         comm       NUMBER(7,2),
         deptno     NUMBER(3) NOT NULL
                     CONSTRAINT admin_dept_fkey REFERENCES hr.departments
                     (department_id))

Posted by: Guest on January-18-2021

Source

SELECT c.OWNER, a.TABLE_NAME, a.COLUMN_NAME, a.CONSTRAINT_NAME, c.R_OWNER AS REF_OWNER, cpk.TABLE_NAME AS REF_TABLE, cpk.CONSTRAINT_NAME AS REF_PK FROM ALL_CONS_COLUMNS a JOIN ALL_CONSTRAINTS c ON a.OWNER = c.OWNER AND a.CONSTRAINT_NAME = c.CONSTRAINT_NAME JOIN ALL_CONSTRAINTS cpk ON c.R_OWNER = cpk.OWNER AND c.R_CONSTRAINT_NAME = cpk.CONSTRAINT_NAME WHERE c.CONSTRAINT_TYPE = 'R' AND c.TABLE_NAME= 'table_name';

SELECT cons.OWNER AS CHILD_OWNER, cons.TABLE_NAME AS CHILD_TABLE, cons.CONSTRAINT_NAME AS CONSTAINT_NAME, cons.CONSTRAINT_TYPE AS CONSTRAINT_TYPE, col.OWNER AS PARENT_OWNER, col.TABLE_NAME AS PARENT_TABLE, col.COLUMN_NAME AS COLUMN_NAME FROM DBA_CONS_COLUMNS col, DBA_CONSTRAINTS cons WHERE cons.R_OWNER = col.OWNER AND cons.R_CONSTRAINT_NAME = col.CONSTRAINT_NAME AND cons.TABLE_NAME = 'table_name';

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