nth highest salary in sql
Here is the solution for nth highest salary from employees table SELECT FIRST_NAME , SALARY FROM (SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER (ORDER BY SALARY DESC) AS SALARY_RANK FROM EMPLOYEES) WHERE SALARY_RANK = n;
nth highest salary in sql
Here is the solution for nth highest salary from employees table SELECT FIRST_NAME , SALARY FROM (SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER (ORDER BY SALARY DESC) AS SALARY_RANK FROM EMPLOYEES) WHERE SALARY_RANK = n;
second max salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
sql find second highest salary employee
/* sql 2nd highest salary employee */ select sal, ename from emp where sal = ( select max(sal) from emp where sal < (select max(sal) from emp) ) ----------------------------------------------- option 2 select * from ( select ename, sal, dense_rank() over(order by sal desc) rank from emp ) where rank =2;
3rd highest salary in sql
Here is the solution for 3rd highest salary from employees table SELECT FIRST_NAME , SALARY FROM (SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER (ORDER BY SALARY DESC) AS SALARY_RANK FROM EMPLOYEES) WHERE SALARY_RANK = 3;
sql highest salary by location
/* Highest salary by Department/Location */ SELECT e.ename, e.sal, e.deptno, d.loc FROM emp e JOIN dept d ON e.deptno = d.deptno WHERE e.sal in ( select max(sal) from emp group by deptno )
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