Answers for "php my admin check"

SQL
0

phpmyadmin CHECK

BEGIN
    IF (DATEDIFF(CURRENT_DATE(),NEW.birth_date) < 6570) THEN

      -- Throw Exception
      SIGNAL SQLSTATE '45000' 
        SET MESSAGE_TEXT = 'Age is less than 18 years!';

    END IF;  -- A semicolon (delimiter) is missing here
END
Posted by: Guest on May-24-2020

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