how to get second highest salary in each department in sql
SELECT E.Employers_name, E.dep_number, E.salary
FROM Employers E
WHERE 1 = (SELECT COUNT(DISTINCT salary)
FROM Employers B
WHERE B.salary > E.salary AND E.dep_number = B.dep_number)
group by E.dep_numbersecond highest salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);
OR
Here is the solution for nth highest
salary from employees table
SELECT FIRST_NAME , SALARY FROM
(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
(ORDER BY SALARY DESC) AS SALARY_RANK
FROM EMPLOYEES)
WHERE SALARY_RANK = n;second max salary in sql
SELECT MAX(SALARY) 'SECOND_MAX' FROM EMPLOYEES
WHERE SALARY <> (SELECT MAX(SALARY) FROM EMPLOYEES);2nd max salary query in sql
select *from employee
group by salary
order by salary desc limit 1,1;3rd highest salary in sql
Here is the solution for 3rd highest
salary from employees table
SELECT FIRST_NAME , SALARY FROM
(SELECT FIRST_NAME, SALARY, DENSE_RANK() OVER
(ORDER BY SALARY DESC) AS SALARY_RANK
FROM EMPLOYEES)
WHERE SALARY_RANK = 3;Copyright © 2021 Codeinu
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