Answers for "partitioning table in oracle"

SQL
0

oracle list partitioned tables

-- List of partitioned tables
SELECT DISTINCT P.TABLE_OWNER, P.TABLE_NAME, count(*) AS NB_PARTITIONS, 
	SP.NB_SUBPARTITIONS
FROM DBA_TAB_PARTITIONS P
LEFT JOIN (SELECT DISTINCT TABLE_OWNER, TABLE_NAME, count(*) AS NB_SUBPARTITIONS
           FROM DBA_TAB_SUBPARTITIONS
           GROUP BY TABLE_OWNER, TABLE_NAME, PARTITION_NAME
          ) SP
ON P.TABLE_OWNER = SP.TABLE_OWNER AND P.TABLE_NAME = SP.TABLE_NAME
WHERE P.TABLE_OWNER NOT IN ('SYS', 'SYSTEM')
GROUP BY P.TABLE_OWNER, P.TABLE_NAME, SP.NB_SUBPARTITIONS
ORDER BY P.TABLE_OWNER, P.TABLE_NAME;
Posted by: Guest on March-19-2021
0

partitioning in oracle-base

CREATE TABLE invoices
(invoice_no    NUMBER NOT NULL,
 invoice_date  DATE   NOT NULL,
 comments      VARCHAR2(500))
PARTITION BY RANGE (invoice_date)
(PARTITION invoices_q1 VALUES LESS THAN (TO_DATE('01/04/2001', 'DD/MM/YYYY')) TABLESPACE users,
 PARTITION invoices_q2 VALUES LESS THAN (TO_DATE('01/07/2001', 'DD/MM/YYYY')) TABLESPACE users,
 PARTITION invoices_q3 VALUES LESS THAN (TO_DATE('01/09/2001', 'DD/MM/YYYY')) TABLESPACE users,
 PARTITION invoices_q4 VALUES LESS THAN (TO_DATE('01/01/2002', 'DD/MM/YYYY')) TABLESPACE users);
Posted by: Guest on October-07-2020

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