find leap year javascript
function isLeap(year) {
if (year % 4 === 0) {
if (year % 100 === 0){
if (year % 400 == 0){
return ("Leap year.");
} else {
return ("Not leap year.");
}
} else {
return ("Leap year.");
}
} else{
return ("Not leap year.");
}
}how to check leap year in javascript
function isLeapYear(year) {
if (year % 400 === 0) return true;
if (year % 100 === 0) return false;
return year % 4 === 0;
}2020 new year
DELETE FROM the_year_2020 WHERE name LIKE "%covid%" OR "%coronavirus%";
-- You know what... to hell with it.
DROP TABLE the_year_2020;Copyright © 2021 Codeinu
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