sum of digits in c++
int x, s = 0;
cout << "Enter the number : ";
cin >> x;
while (x != 0) {
s = s + x % 10;
x = x / 10;
}sum of digits in c++
int x, s = 0;
cout << "Enter the number : ";
cin >> x;
while (x != 0) {
s = s + x % 10;
x = x / 10;
}C++ sum the digits of an integer
// sum the digits of an integer
int getSum(long long n) {
int sum = 0;
int m = n;
while(n > 0) {
m = n % 10;
sum = sum + m;
n = n / 10;
}
return sum;
}c++ sum up numbers
// Method 1: Mathematical -> Sum up numbers from 1 to n
int sum(int n){
return (n * (n+1)) / 2;
}
// Method 2: Using a for-loop -> Sum up numbers from 1 to n
int sum(int n){
int tempSum = 0;
for (int i = n; i > 0; i--){
tempSum += i;
}
return tempSum;
}
// Method 3: Using recursion -> Sum up numbers from 1 to n
int sum(int n){
return n > 0 ? n + sum(n-1) : 0;
}digit sum c++
//1
int n = 12345, sum = 0;
while(n) {
sum+=n%10;
n/=10;
}
cout << sum; //15
//2
int n = 12345, sum = 0;
for (sum = 0; n > 0; sum += n % 10, n /= 10);
cout << sum; //15Copyright © 2021 Codeinu
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