Answers for "do and tap operator rxjs"

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do and tap operator rxjs

const source = of(1, 2, 3, 4);
source.pipe(
  tap(val => console.log('I am tap: ',val)),
  filter(val =>  val > 2),
  map(val => val + 1)).subscribe((val) => {
  console.log('I am subscriber value after filtering: ', val);
});

Posted by: Guest on June-14-2021

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