Answers for "fetch catch"

21

fetch json post

(async () => {
  const rawResponse = await fetch('https://httpbin.org/post', {
    method: 'POST',
    headers: {
      'Accept': 'application/json',
      'Content-Type': 'application/json'
    },
    body: JSON.stringify({a: 1, b: 'Textual content'})
  });
  const content = await rawResponse.json();

  console.log(content);
})();
Posted by: Guest on May-07-2020
35

js fetch 'post' json

//Obj of data to send in future like a dummyDb
const data = { username: 'example' };

//POST request with body equal on data in JSON format
fetch('https://example.com/profile', {
  method: 'POST',
  headers: {
    'Content-Type': 'application/json',
  },
  body: JSON.stringify(data),
})
.then((response) => response.json())
//Then with the data from the response in JSON...
.then((data) => {
  console.log('Success:', data);
})
//Then with the error genereted...
.catch((error) => {
  console.error('Error:', error);
});

//																		Yeah
Posted by: Guest on March-28-2020
3

javascript fetch json

fetch('./yourjson.json')
  .then((response) => response.json())
  .then((data) => {
  	console.log(data);
  })
Posted by: Guest on December-07-2020
2

try catch fetch

fetch("/api/foo")
  .then( response => {
    if (!response.ok) { throw response }
    return response.json()  //we only get here if there is no error
  })
  .then( json => {
    this.props.dispatch(doSomethingWithResult(json)) 
  })
  .catch( err => {
    err.text().then( errorMessage => {
      this.props.dispatch(displayTheError(errorMessage))
    })
  })
Posted by: Guest on March-15-2021
4

fetch suntax

fetch('http://example.com/movies.json')
  .then((response) => {
    return response.json();
  })
  .then((data) => {
    console.log(data);
  });
Posted by: Guest on March-16-2020
0

fetch catch

fetch(url).then((response) => {
  if (response.ok) {
    return response.json();
  } else {
    throw new Error('Something went wrong');
  }
})
.then((responseJson) => {
  // Do something with the response
})
.catch((error) => {
  console.log(error)
});
Posted by: Guest on March-17-2021

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