javascript map
function listFruits() {
let fruits = ["apple", "cherry", "pear"]
fruits.map((fruit, index) => {
console.log(index, fruit)
})
}
listFruits()
// https://jsfiddle.net/tmoreland/16qfpkgb/3/javascript map
function listFruits() {
let fruits = ["apple", "cherry", "pear"]
fruits.map((fruit, index) => {
console.log(index, fruit)
})
}
listFruits()
// https://jsfiddle.net/tmoreland/16qfpkgb/3/array map javascript
const array1 = [1, 4, 9, 16];
// pass a function to map
const map1 = array1.map(x => x * 2);
console.log(map1);
// expected output: Array [2, 8, 18, 32]array map
const array1 = [1, 4, 9, 16];
// pass a function to map
const map1 = array1.map(x => x * 2);
console.log(map1);
// expected output: Array [2, 8, 18, 32]array map
let numbers = [1, 2, 3, 4]
let filteredNumbers = numbers.map(function(_, index) {
if (index < 3) {
return num
}
})
// index goes from 0, so the filterNumbers are 1,2,3 and undefined.
// filteredNumbers is [1, 2, 3, undefined]
// numbers is still [1, 2, 3, 4]array map
let numbers = [1, 2, 3, 4]
let filteredNumbers = numbers.map(function(num, index) {
if (index < 3) {
return num
}
})
// index goes from 0, so the filterNumbers are 1,2,3 and undefined.
// filteredNumbers is [1, 2, 3, undefined]
// numbers is still [1, 2, 3, 4]array map
let numbers = [1, 4, 9]
let roots = numbers.map(function(num) {
return Math.sqrt(num)
})
// roots is now [1, 2, 3]
// numbers is still [1, 4, 9]Copyright © 2021 Codeinu
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