last index of a number using recursion
int lastIndex(int input[], int size, int x)
{
if (size == 0)
{
return -1;
}
int answer = lastIndex(input + 1, size - 1, x);
if (answer != -1)
{
return answer + 1;
}
if (input[0] == x)
{
return 0;
}
else
{
return -1;
}
}
int main()
{
int input[] = {9, 8, 10, 8};
int x = 8;
int size = 4;
cout << lastIndex(input, size, x);
return 0;
}last index of a number using recursion
int rLookupAr (int array[], int size, int target)
{
if(size<=0) return -1;
if(array[size-1] == target)
return size-1;
else
return rLookupAr (array, size-1, target); //recurse
}last index of a number using recursion
int rLookupAr(int array[], int size, int target)
{
if(size < 1) return -1;
size--;
if(array[size] == target) return size;
return rLookupAr(array, size,target);
}Copyright © 2021 Codeinu
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