Answers for "(41,55) error cs1003 syntax error unity jump"

0

(41,55) error cs1003 syntax error unity jump

using System.Collections;
using System.Collections.Generic;
using UnityEngine;

public class playermovement : MonoBehaviour
{
    public CharacterController controller;
  
           public float speed = 12f;
     public float gravity = -9.81f;
     public float jumpheight = 3f;

     public Transform groundCheck;
     public float groundDistance = 0.4f;
     public LayerMask groundMask;

     Vector3 velocity;
     bool isGrounded; 
     
     
    // Start is called before the first frame update
    void Start()
    {

    }

    // Update is called once per frame
    void Update()
    {


        float x = Input.GetAxis("Horizontal");
        float z = Input.GetAxis("Vertical");

        Vector3 move = transform.right * x + transform.forward * z;

         controller.Move(move * speed * Time.deltaTime);

         if(Input.Get.ButtonDown("jump") && isGrounded)
         {
             velocity.y = Mathf.Sqrt(jumpheight * -2f gravity);
         }

         velocity.y += gravity * Time.deltaTime;

         controller.Move(velocity * Time.deltaTime);
    }
}
Posted by: Guest on August-26-2021

Code answers related to "(41,55) error cs1003 syntax error unity jump"

Browse Popular Code Answers by Language