Answers for "#pragma pack(1) in c"

Whatever

#pragma pack(1) in c

adds  r31 = r32, 4
adds  r30 = r32  8 ;;
ld1   r29 = [r31], 1
ld1   r28 = [r30], 1 ;;
ld1   r27 = [r31], 1
ld1   r26 = [r30], 1 ;;
dep   r29 = r27, r29, 8, 8
dep   r28 = r26, r28, 8, 8
ld1   r25 = [r31], 1
ld1   r24 = [r30], 1 ;;
dep   r29 = r25, r29, 16, 8
dep   r28 = r24, r28, 16, 8
ld1   r27 = [r31]
ld1   r26 = [r30] ;;
dep   r29 = r27, r29, 24, 8
dep   r28 = r26, r28, 24, 8 ;;
add   r31 = r28, r29 ;;
st1   [r32] = r31
adds  r30 = r32, 1
adds  r29 = r32, 2 
extr  r28 = r31, 8, 8
extr  r27 = r31, 16, 8 ;;
st1   [r30] = r28
st1   [r29] = r27, 1
extr  r26 = r31, 24, 8 ;;
st1   [r29] = r26
br.ret.sptk.many.rp

Posted by: Guest on October-16-2020

Source

#pragma pack(1) in c

struct Test
{
   char AA;
   int BB;
   char CC;
};

Posted by: Guest on October-16-2020

Source

#pragma pack(1) in c

adds  r31 = r32, 4
adds  r30 = r32  8 ;;
ld4   r31 = [r31]
ld4   r30 = [r30] ;;












add   r31 = r30, r31 ;;
st4   [r32] = r31








br.ret.sptk.many rp

Posted by: Guest on October-16-2020

Source

#pragma pack(1) in c

#include <stdio.h>

struct a {
    char one;
    char two[2];
    char eight[8];
    char four[4];
};

struct b { 
    char one;
    short two;
    long int eight;
    int four;
};

int main(int argc, char** argv) {
    struct a twoa[2] = {}; 
    struct b twob[2] = {}; 
    printf("sizeof(struct a): %i, sizeof(struct b): %i\n", sizeof(struct a), sizeof(struct b));
    printf("sizeof(twoa): %i, sizeof(twob): %i\n", sizeof(twoa), sizeof(twob));
}

Posted by: Guest on October-16-2020

Source

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