read xml file c#
XmlDocument doc = new XmlDocument();
using (StreamReader streamReader = new StreamReader(path_name, Encoding.UTF8))
{
contents = streamReader.ReadToEnd();
}
doc.LoadXml(contents);read xml file c#
XmlDocument doc = new XmlDocument();
using (StreamReader streamReader = new StreamReader(path_name, Encoding.UTF8))
{
contents = streamReader.ReadToEnd();
}
doc.LoadXml(contents);Read XML
from bs4 import BeautifulSoup
soup = BeautifulSoup(open('W2Testfile.xml', encoding='utf-8'), 'lxml')
# Just copy from and doc and lower search or write lower case
sub_id = soup.find('SubmissionId'.lower())
# Tag and text
print(sub_id)
print(sub_id.text)
#---| Take out part eg doc 2,then <find_all> of a tag that there are several of
doc_2 = soup.find('returndata', {'documentcnt': '2'})
dep_detail = doc_2.find_all('DependentDetail'.lower())
print('-' * 30)
print(dep_detail[0].find('dependentrelationshipcd'))
print(dep_detail[0].find('dependentrelationshipcd').text)how to read an xml file
import xmltodict as xtd
import os
xml_file_content = ""
catalog_dir = os.chdir('directory')
catalog_dir_array = os.listdir(catalog_dir)
if("nameOfFile.xml" in catalog_dir_array):
catalog_file_content = open("nameOfFile.xml", "r").read()
catalog_file_content_dict = xtd.parse(catalog_file_content)Copyright © 2021 Codeinu
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