What's method overloading
Overloading mean same method name and different parameter,
it can happen in same class. it's a feature that
allows us to have more than one method with same name.
Example: sort method of Arrays class
Arrays.sort(int[] arr)
Arrays.sort(String[] arr)
....
Method overloading improves the reusability and readability.
and it's easy to remember
(one method name instead of remembering multiple method names)method overloading
//https://www.geeksforgeeks.org/overloading-in-java/
// Java program to demonstrate working of method
// overloading in Java.
public class Sum {
// Overloaded sum(). This sum takes two int parameters
public int sum(int x, int y)
{
return (x + y);
}
// Overloaded sum(). This sum takes three int parameters
public int sum(int x, int y, int z)
{
return (x + y + z);
}
// Overloaded sum(). This sum takes two double parameters
public double sum(double x, double y)
{
return (x + y);
}
// Driver code
public static void main(String args[])
{
Sum s = new Sum();
System.out.println(s.sum(10, 20));
System.out.println(s.sum(10, 20, 30));
System.out.println(s.sum(10.5, 20.5));
}
}java overload
int MyMethod(int x)
float MyMethod(float x)
double MyMethod(double x, double y)java overloading
class CalculateSquare
{
public void square()
{
System.out.println("No Parameter Method Called");
}
public int square( int number )
{
int square = number * number;
System.out.println("Method with Integer Argument Called:"+square);
}
public float square( float number )
{
float square = number * number;
System.out.println("Method with float Argument Called:"+square);
}
public static void main(String[] args)
{
CalculateSquare obj = new CalculateSquare();
obj.square();
obj.square(5);
obj.square(2.5);
}
}Copyright © 2021 Codeinu
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