Answers for "preorder to postorder gfg practice"

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preorder to postorder gfg practice

Node* constructTree(int pre[], int n)
{
    Node* root= newNode(pre[0]);
    Node* temp=root;
    stack<Node*>st;
    st.push(root);
    int i=0;
    while(i<n)
    {
        if(st.top()->data>pre[i])
        { 
           temp=st.top();
           temp->left= newNode(pre[i]);
           st.push(temp->left);
           //temp=temp->left;

        }
        Node* curr=NULL;
            while(!st.empty()&&(st.top()->data<pre[i]))
            {
                curr=st.top();
                st.pop();
            }
            if(curr)
            {
            curr->right=newNode(pre[i]);
            st.push(curr->right);
            }
        i++;
    }
    return root;
 
}
Posted by: Guest on June-01-2021

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