postgres date difference seconds
-- difference in seconds between two dates
select extract(epoch from ('2020-03-30 09:55:56'::timestamp - '2020-03-30 08:54:55'::timestamp));
-- result : 3661postgres date difference seconds
-- difference in seconds between two dates
select extract(epoch from ('2020-03-30 09:55:56'::timestamp - '2020-03-30 08:54:55'::timestamp));
-- result : 3661postgresql get difference between two dates
select age('2010-04-01', '2012-03-05'),
date_part('year',age('2010-04-01', '2012-03-05')),
date_part('month',age('2010-04-01', '2012-03-05')),
date_part('day',age('2010-04-01', '2012-03-05'));postgres time difference in minutes
CREATE OR REPLACE FUNCTION DateDiff (units VARCHAR(30), start_t TIME, end_t TIME)
RETURNS INT AS $$
DECLARE
diff_interval INTERVAL;
diff INT = 0;
BEGIN
-- Minus operator for TIME returns interval 'HH:MI:SS'
diff_interval = end_t - start_t;
diff = DATE_PART('hour', diff_interval);
IF units IN ('hh', 'hour') THEN
RETURN diff;
END IF;
diff = diff * 60 + DATE_PART('minute', diff_interval);
IF units IN ('mi', 'n', 'minute') THEN
RETURN diff;
END IF;
diff = diff * 60 + DATE_PART('second', diff_interval);
RETURN diff;
END;
$$ LANGUAGE plpgsql;postgres get number of days between two dates
SELECT
AGE('2012-03-05', '2010-04-01'),
DATE_PART('year', AGE('2012-03-05', '2010-04-01')) AS years,
DATE_PART('month', AGE('2012-03-05', '2010-04-01')) AS months,
DATE_PART('day', AGE('2012-03-05', '2010-04-01')) AS days;Copyright © 2021 Codeinu
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