Answers for "np_resource = np.dtype([("resource", np.ubyte, 1)])"

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FutureWarning: Passing (type, 1) or '1type' as a synonym of type is deprecated; in a future version of numpy, it will be understood as (type, (1,)) / '(1,)type'. _np_quint8 = np.dtype([("quint8", np.uint8, 1)])'

1. pip uninstall numpy 
2. pip install numpy==1.16.4
Posted by: Guest on June-13-2020

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