Answers for "boto3 s3 list objects get file info"

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1

list file in s3 boto

import boto3

s3 = boto3.resource('s3')
my_bucket = s3.Bucket('my_bucket_name')

for object_summary in my_bucket.objects.filter(Prefix="dir_name/"):
    print(object_summary.key)

Posted by: Guest on November-30-2020

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