submit form when checkbox is checked
onChange="this.form.submit()"submit form when checkbox is checked
onChange="this.form.submit()"checkbox onchange submit form
<form method='post' action='#'>
<input type='checkbox' name='checkbox' onChange='submit();'
<?php if($page->checkbox_state == 1) { echo 'checked' }; ?>>
</form>Copyright © 2021 Codeinu
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