max value in array javascript
// For large data, it's better to use reduce. Supose arr has a large data in this case:
const arr = [1, 5, 3, 5, 2];
const max = arr.reduce((a, b) => { return Math.max(a, b) });
// For arrays with relatively few elements you can use apply:
const max = Math.max.apply(null, arr);
// or spread operator:
const max = Math.max(...arr);find maximum number in array
#include <stdio.h>
int main() {
int i, n;
float arr[100];
printf("Enter the number of elements (1 to 100): ");
scanf("%d", &n);
for (i = 0; i < n; ++i) {
printf("Enter number%d: ", i + 1);
scanf("%f", &arr[i]);
}
// storing the largest number to arr[0]
for (i = 1; i < n; ++i) {
if (arr[0] < arr[i])
arr[0] = arr[i];
}
printf("Largest element = %.2f", arr[0]);
return 0;
}js max value of array
let numbers = [4, 13, 27, 0, -5]; // Get max value of an array in Javascript
Math.max.apply(null, numbers); // returns 27how to find max in array
int[] a = new int[] { 20, 30, 50, 4, 71, 100};
int max = a[0];
for(int i = 1; i < a.length;i++)
{
if(a[i] > max)
{
max = a[i];
}
}
System.out.println("The Given Array Element is:");
for(int i = 0; i < a.length;i++)
{
System.out.println(a[i]);
}
System.out.println("From The Array Element Largest Number is:" + max);find max and min value in array javascript
var numbers = [1, 2, 3, 4];
Math.max(...numbers) // 4
Math.min(...numbers) // 1max element in array
int max;
max=INT_MIN;
for(int i=0;i<ar.length();i++){
if(ar[i]>max){
max=ar[i];
}Copyright © 2021 Codeinu
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