find number of digits in a number
floor(log10(n) + 1);calc the number of digits
int count = 0;
int n = number;
while (n != 0)
{
n /= 10;
cout++;
}number of digits calculation
number_of_digits = 0
a_variable = input
while a_variable >= 1:
number_of_digits += 1
a_variable /= 10
#Just translated Kind Kinkajou's answer to python.
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