JS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortJS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortjavascript sort
var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]
var objs = [
{name: "Peter", age: 35},
{name: "Emma", age: 21},
{name: "Jack", age: 53}
];
objs.sort(function(a, b) {
return a.age - b.age;
}); // Sort by age (lowest first)array sort js
arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]
arr.sort((a,b) => a.localeCompare(b))
// if a-b (based on their unicode values) produces a negative value,
// a comes before b, the reverse if positive, and as is if zero
//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items
//this explnation in not minesorting in js
var arr = [23, 34343, 1, 5, 90, 9]
//using forEach
var sortedArr = [];
arr.forEach(x => {
if (sortedArr.length == 0)
sortedArr.push(x)
else {
if (sortedArr[0] > x) sortedArr.unshift(x)
else if (sortedArr[sortedArr.length - 1] < x) sortedArr.push(x)
else sortedArr.splice(sortedArr.filter(y => y < x).length, 0, x)
}
})
console.log(sortedArr);
// using sort method
console.log(arr.sort((a,b)=>{
return a-b;
}));sort function explained javascript
var sortedArray = myArray.sort(function(a,b){
if (a.name < b.name)
return -1;
else if (a.name == b.name)
return 0;
else
return 1;
});Copyright © 2021 Codeinu
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