sorting array from highest to lowest javascript
// Sort an array of numbers
let numbers = [5, 13, 1, 44, 32, 15, 500]
// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]
//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]js order alphabetically
// Alphabetically
const ascending = data.sort((a, b) => a[field].localeCompare(b[field]))
// Descending
const descending = ascending.reverse()ascending and descending val in array using js
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortjs sort numbers descending order
// Sort Numbers in Descending Order
function sortDescending(num) {
return Number(num.toString().split('').sort((a, b) => b - a).join(''));
//or: return parseInt(num.toString().split('').sort().reverse().join(''));
}
console.log(sortDescending(123)); // 321
console.log(sortDescending(1254859723)); // 9875543221javascript ascending and descending
// ascending and discending for number
const arr1 = [21, 2100, 2, 35000];
const arr2 = [21, 2100, 2, 35000];
let ascN = arr1.sort((f, s) => f - s);
let dscN = arr2.sort((f, s) => s - f);
// ascending and discending for string
const arr3 = ['21', '2100', '2', '35000'];
const arr4 = ['21', '2100', '2', '35000'];
let ascS = arr3.sort((f, s) => f.length - s.length);
let dscS = arr4.sort((f, s) => s.length - f.length);Copyright © 2021 Codeinu
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