JS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortJS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortjs sort
let numbers = [4, 10, 5, 1, 3];
numbers.sort((a, b) => a - b);
console.log(numbers);
// [1, 2, 3, 4, 5]array sort js
arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]
arr.sort((a,b) => a.localeCompare(b))
// if a-b (based on their unicode values) produces a negative value,
// a comes before b, the reverse if positive, and as is if zero
//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items
//this explnation in not minejavascript sort
homes.sort(function(a, b) {
return parseFloat(a.price) - parseFloat(b.price);
});javascript sort
homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));sorting array
def merge_sort(array, left_index, right_index):
if left_index >= right_index:
return
middle = (left_index + right_index)//2
merge_sort(array, left_index, middle)
merge_sort(array, middle + 1, right_index)
merge(array, left_index, right_index, middle)Copyright © 2021 Codeinu
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