JS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortJS array sort
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortsort array java
Here’s the java program to sort an array using Arrays.sort() method.
import java.util.Arrays;
public class JavaArraySortMethod
{
public static void main(String[] args)
{
String[] strGiven = {"Great Barrier Reef", "Paris", "borabora", "Florence","tokyo", "Cusco"};
Arrays.sort(strGiven);
System.out.println("Output(case sensitive) : " + Arrays.toString(strGiven));
}
}how to sort integer array in java
int countOfArray = 5;
int num [] = new int[counfOfArray];
int num[] = [8 , 5 , 9 , 3 , 4];
for (int i = 0; i < countOfArray; i++)
{
for (int j = i + 1; j < countOfArray; j++) {
if (num[i] > num[j])
{
temp = num[i];
num[i] = num[j];
num[j] = temp;
}
}
}javascript sort
var names = ["Peter", "Emma", "Jack", "Mia", "Eric"];
names.sort(); // ["Emma", "Eric", "Jack", "Mia", "Peter"]
var objs = [
{name: "Peter", age: 35},
{name: "Emma", age: 21},
{name: "Jack", age: 53}
];
objs.sort(function(a, b) {
return a.age - b.age;
}); // Sort by age (lowest first)js sort
let numbers = [4, 10, 5, 1, 3];
numbers.sort((a, b) => a - b);
console.log(numbers);
// [1, 2, 3, 4, 5]array sort js
arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]
arr.sort((a,b) => a.localeCompare(b))
// if a-b (based on their unicode values) produces a negative value,
// a comes before b, the reverse if positive, and as is if zero
//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items
//this explnation in not mineCopyright © 2021 Codeinu
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