sorting array from highest to lowest javascript
// Sort an array of numbers
let numbers = [5, 13, 1, 44, 32, 15, 500]
// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]
//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]javascript sort
homes.sort(function(a, b) {
return parseFloat(a.price) - parseFloat(b.price);
});javascript sort
homes.sort((a, b) => parseFloat(a.price) - parseFloat(b.price));how to sort an array
import java.util.Scanner;
public class JavaExample
{
public static void main(String[] args)
{
int count, temp;
//User inputs the array size
Scanner scan = new Scanner(System.in);
System.out.print("Enter number of elements you want in the array: ");
count = scan.nextInt();
int num[] = new int[count];
System.out.println("Enter array elements:");
for (int i = 0; i < count; i++)
{
num[i] = scan.nextInt();
}
scan.close();
for (int i = 0; i < count; i++)
{
for (int j = i + 1; j < count; j++) {
if (num[i] > num[j])
{
temp = num[i];
num[i] = num[j];
num[j] = temp;
}
}
}
System.out.print("Array Elements in Ascending Order: ");
for (int i = 0; i < count - 1; i++)
{
System.out.print(num[i] + ", ");
}
System.out.print(num[count - 1]);
}
}sort function explained javascript
var sortedArray = myArray.sort(function(a,b){
if (a.name < b.name)
return -1;
else if (a.name == b.name)
return 0;
else
return 1;
});Copyright © 2021 Codeinu
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