sorting array from highest to lowest javascript
// Sort an array of numbers
let numbers = [5, 13, 1, 44, 32, 15, 500]
// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]
//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]sort js
numArray.sort((a, b) => a - b); // For ascending sort
numArray.sort((a, b) => b - a); // For descending sortarray sort js
arr = ['width', 'score', done', 'neither' ]
arr.sort() // results to ["done", "neither", "score", "width"]
arr.sort((a,b) => a.localeCompare(b))
// if a-b (based on their unicode values) produces a negative value,
// a comes before b, the reverse if positive, and as is if zero
//When you sort an array with .sort(), it assumes that you are sorting strings
//. When sorting numbers, the default behavior will not sort them properly.
arr = [21, 7, 5.6, 102, 79]
arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102]
// b - a will give you the reverse order of the sorted items
//this explnation in not mineCopyright © 2021 Codeinu
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