sorting array from highest to lowest javascript
// Sort an array of numbers
let numbers = [5, 13, 1, 44, 32, 15, 500]
// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]
//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]javascript orderby
var items = [
{ name: 'Edward', value: 21 },
{ name: 'Sharpe', value: 37 },
{ name: 'And', value: 45 },
{ name: 'The', value: -12 },
{ name: 'Magnetic', value: 13 },
{ name: 'Zeros', value: 37 }
];
// sort by value
items.sort(function (a, b) {
return a.value - b.value;
});
// sort by name
items.sort(function(a, b) {
var nameA = a.name.toUpperCase(); // ignore upper and lowercase
var nameB = b.name.toUpperCase(); // ignore upper and lowercase
if (nameA < nameB) {
return -1;
}
if (nameA > nameB) {
return 1;
}
// names must be equal
return 0;
});sort in js
var points = [40, 100, 1, 5, 25, 10];
points.sort((a,b) => a-b)javascript sort array in ascending order
//sorts arrays of numbers
function myFunction() {
points.sort(function(a, b){return a-b});
document.getElementById("demo").innerHTML = points;
}sort() function example JavaScript
function ascendingOrder(arr) {
return arr.sort(function(a, b) {
return a - b;
});
}
ascendingOrder([1, 5, 2, 3, 4]);sort function explained javascript
var sortedArray = myArray.sort(function(a,b){
if (a.name < b.name)
return -1;
else if (a.name == b.name)
return 0;
else
return 1;
});Copyright © 2021 Codeinu
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