sorting array from highest to lowest javascript
// Sort an array of numbers let numbers = [5, 13, 1, 44, 32, 15, 500] // Lowest to highest let lowestToHighest = numbers.sort((a, b) => a - b); //Output: [1,5,13,15,32,44,500] //Highest to lowest let highestToLowest = numbers.sort((a, b) => b-a); //Output: [500,44,32,15,13,5,1]
JS array sort
numArray.sort((a, b) => a - b); // For ascending sort numArray.sort((a, b) => b - a); // For descending sort
sort js
numArray.sort((a, b) => a - b); // For ascending sort numArray.sort((a, b) => b - a); // For descending sort
js sort
let numbers = [4, 10, 5, 1, 3]; numbers.sort((a, b) => a - b); console.log(numbers); // [1, 2, 3, 4, 5]
array sort js
arr = ['width', 'score', done', 'neither' ] arr.sort() // results to ["done", "neither", "score", "width"] arr.sort((a,b) => a.localeCompare(b)) // if a-b (based on their unicode values) produces a negative value, // a comes before b, the reverse if positive, and as is if zero //When you sort an array with .sort(), it assumes that you are sorting strings //. When sorting numbers, the default behavior will not sort them properly. arr = [21, 7, 5.6, 102, 79] arr.sort((a, b) => a - b) // results to [5.6, 7, 21, 79, 102] // b - a will give you the reverse order of the sorted items //this explnation in not mine
how the sort function works javascript
const unsorted = ['d', 'd', 'h', 'r', 'v', 'z', 'f', 'c', 'g']; const sorted = unsorted.sort(); console.log(sorted); //["c", "d", "d", "f", "g", "h", "r", "v", "z"] const unsortedNums = [45, 56, 3, 3, 4, 6, 7, 45, 1]; const sortedNums = unsortedNums.sort((a, b) => { return a - b; }); console.log(sortedNums); //[1, 3, 3, 4, 6, 7, 45, 45, 56]
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