Answers for "sort array in descending order js"

14

sorting array from highest to lowest javascript

// Sort an array of numbers 
let numbers = [5, 13, 1, 44, 32, 15, 500]

// Lowest to highest
let lowestToHighest = numbers.sort((a, b) => a - b);
//Output: [1,5,13,15,32,44,500]

//Highest to lowest
let highestToLowest = numbers.sort((a, b) => b-a);
//Output: [500,44,32,15,13,5,1]
Posted by: Guest on March-25-2020
3

javascript ascending and descending

// ascending and discending for number
const arr1 = [21, 2100, 2, 35000];
const arr2 = [21, 2100, 2, 35000];

let ascN = arr1.sort((f, s) => f - s);
let dscN = arr2.sort((f, s) => s - f);

// ascending and discending for string
const arr3 = ['21', '2100', '2', '35000'];
const arr4 = ['21', '2100', '2', '35000'];

let ascS = arr3.sort((f, s) => f.length - s.length);
let dscS = arr4.sort((f, s) => s.length - f.length);
Posted by: Guest on June-21-2020
13

javascript orderby

var items = [
  { name: 'Edward', value: 21 },
  { name: 'Sharpe', value: 37 },
  { name: 'And', value: 45 },
  { name: 'The', value: -12 },
  { name: 'Magnetic', value: 13 },
  { name: 'Zeros', value: 37 }
];

// sort by value
items.sort(function (a, b) {
  return a.value - b.value;
});

// sort by name
items.sort(function(a, b) {
  var nameA = a.name.toUpperCase(); // ignore upper and lowercase
  var nameB = b.name.toUpperCase(); // ignore upper and lowercase
  if (nameA < nameB) {
    return -1;
  }
  if (nameA > nameB) {
    return 1;
  }

  // names must be equal
  return 0;
});
Posted by: Guest on May-30-2020
2

javascript sort descending

function sortEggsInNest(a, b) {
  return a > b ? -1 : b > a ? 1 : 0;
}
Posted by: Guest on March-19-2021
7

javascript sort

homes.sort(function(a, b) {
    return parseFloat(a.price) - parseFloat(b.price);
});
Posted by: Guest on March-17-2020
0

sort array descending

testsSortedByNome = tests.sort((a, b) => (a.nome > b.nome ? -1 : 1));
testsSortedByCognome = tests.sort((a, b) => (a.cognome > b.cognome ? -1 : 1));
Posted by: Guest on June-15-2021

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