javascript ascending and descending
// ascending and discending for number
const arr1 = [21, 2100, 2, 35000];
const arr2 = [21, 2100, 2, 35000];
let ascN = arr1.sort((f, s) => f - s);
let dscN = arr2.sort((f, s) => s - f);
// ascending and discending for string
const arr3 = ['21', '2100', '2', '35000'];
const arr4 = ['21', '2100', '2', '35000'];
let ascS = arr3.sort((f, s) => f.length - s.length);
let dscS = arr4.sort((f, s) => s.length - f.length);javascript orderby
var items = [
{ name: 'Edward', value: 21 },
{ name: 'Sharpe', value: 37 },
{ name: 'And', value: 45 },
{ name: 'The', value: -12 },
{ name: 'Magnetic', value: 13 },
{ name: 'Zeros', value: 37 }
];
// sort by value
items.sort(function (a, b) {
return a.value - b.value;
});
// sort by name
items.sort(function(a, b) {
var nameA = a.name.toUpperCase(); // ignore upper and lowercase
var nameB = b.name.toUpperCase(); // ignore upper and lowercase
if (nameA < nameB) {
return -1;
}
if (nameA > nameB) {
return 1;
}
// names must be equal
return 0;
});sorting of arraray's number element in javascript
let numbers = [0, 1, 2, 3, 10, 20, 30];
numbers.sort((a, b) => a - b);
console.log(numbers);sort array descending
testsSortedByNome = tests.sort((a, b) => (a.nome > b.nome ? -1 : 1));
testsSortedByCognome = tests.sort((a, b) => (a.cognome > b.cognome ? -1 : 1));Copyright © 2021 Codeinu
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