Answers for "js sort ascending number"

9

javascript sort by numerical value

// Sort an array of numbers based on numerical value.
let numbers = [23, 65, 88, 12, 45, 99, 2000]

let sortednumbers = numbers.sort((a, b) => a - b);
//=> [12, 23, 45, 65, 88, 99, 2000]
Posted by: Guest on February-28-2020
0

js sort numbers descending order

// Sort Numbers in Descending Order
function sortDescending(num) {
	return Number(num.toString().split('').sort((a, b) => b - a).join(''));
//or: return parseInt(num.toString().split('').sort().reverse().join(''));
}

console.log(sortDescending(123)); // 321
console.log(sortDescending(1254859723)); // 9875543221
Posted by: Guest on March-12-2021
0

javascript sort numbers

var numArray = [140000, 104, 99];

numArray.sort(function(a, b) {
  return a - b;
});

// Array(3) [ 99, 104, 140000 ]
Posted by: Guest on January-27-2021
1

sort by ascending javascript

const months = ['March', 'Jan', 'Feb', 'Dec'];
months.sort();
console.log(months);
// expected output: Array ["Dec", "Feb", "Jan", "March"]
Posted by: Guest on October-28-2020

Browse Popular Code Answers by Language