Answers for "sum of even digits in c"

C
1

Find Numbers with Even Number of Digits in c

/* Find Numbers with Even Number of Digits in c */

/**
* numDigit - gives the length of a given number
* @n: the number
*/
int numDigit(int n){
        int d = 0;
        
        while (n > 0 && n < 100000){
                n = n/10;
                d++; 
        }
        return(d);
}

/**
* findNumbers - returns the number of numbers with even number of digits
* @*nums: a pointer to a num array
* @numSize: the size of the array
*/
int findNumbers(int* nums, int numsSize){
        
        int c = 0;
        
        for(int i = 0; i < numsSize; i++){
                
                if(numDigit(nums[i]) % 2 == 0){
                        c++;
                } 
                
        }
        return(c);
}
Posted by: Guest on August-19-2021
0

sum of individual digits in c using function

#include <stdio.h>

int individualSum(num);

void main ()
{
    int num, ret;

    ret = individualSum(num);
    printf("nThe sum of individual digit is %dn", ret);
}

int individualSum(num)
{
    int i, rem, sum = 0;
    printf("Enter the number: ");
    scanf("%d",&num);

    while(num!=0)
    {
        rem = num % 10;
        num = num /10;
        sum = sum + rem;
    }
  	
  return sum;
}
Posted by: Guest on June-23-2021
0

C program to calculate the sum of odd and even numbers

#include <stdio.h>void main(){int i, number, odd_sum = 0, even_sum = 0;printf("Enter the value of numbern");scanf("%d", &number);for (i = 1; i <= number; i++){if (i % 2 == 0)even_sum = even_sum + i;elseodd_sum = odd_sum + i;}printf("Sum of all odd numbers = %dn", odd_sum);printf("Sum of all even numbers = %dn", even_sum);}
Posted by: Guest on July-08-2021

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